Calculus I Lesson 3: More on Limits
Warm Up
- Graph $f(x) = \frac{x^3-1}{x^2-1}$. (Graphing calculator / Desmos)
- For the points where $f(x)$ is not defined, does the graph of $f$ appear to approach a particular (finite) value?
- Use the distributive property to show $x^3 - 1 = (x-1)(x^2+x+1)$ and $x^2 - 1 = (x-1)(x+1)$.
- Simplify $\frac{(x-1)(x^2+x+1)}{(x-1)(x+1)}$.
Graph
- Notice that ${\displaystyle \lim_{x \rightarrow 1}} f(x) = \frac{3}{2}$. But $f(1)$ is not defined?
- Whenever $x \neq 1$, $f(x) = \frac{x^2+x+1}{x+1}$. So, as $x \rightarrow 1$, $f(x) \rightarrow \frac{1+1+1}{1+1} = \frac{3}{2}$.
- What happens as $x \rightarrow -1$?
- Numerator $\rightarrow -2$, denominator $\rightarrow 0$.
- Nothing cancels.
- Hence: asymptote! ($\frac{-2}{.000001}$ is a large negative number)
Questions from DeltaMath?
Recall
- ${\displaystyle\lim_{x\rightarrow a^-}} f(x)$ refers to the limit as $x \rightarrow a$ from the left.
- ${\displaystyle\lim_{x\rightarrow a^+}} f(x)$ refers to the limit as $x \rightarrow a$ from the right.
- If both of the above exist and are equal, then ${\displaystyle \lim_{x\rightarrow a}}f(x)$ exists, and is equal to them both.
Computing Limits
3 ways to compute limits:
- Direct substitution
- Algebraic manipulation
- Squeeze Theorem
Eventually: 4th way (l’Hôpital’s rule). If you know that: don’t use it yet.
Direct Substitution
Easiest method. Works for “nicely behaved functions”:
- Polynomials
- Rational functions, if the denominator is not 0
- sin, cos, tan (if defined)
- exponential, logarithmic functions (if defined)
These functions are continuous.
Algebraic Manipulation
- Can we cancel something?
- Can we multiply by a conjugate?
In other words: can we make our function equivalent to one of the ones where we can use direct substitution, except possibly at one, isolated point? (Ex: warm-up)
(Later: squeeze theorem.)
Exercise
Use algebraic manipulation to compute these limits:
- ${\displaystyle \lim_{x\rightarrow 2}} \frac{x^2-4x+4}{x^2-4}$
- ${\displaystyle \lim_{x\rightarrow 0}} \frac{x}{x^3}$
Conjugates
${\displaystyle \lim_{x \rightarrow 4}}\frac{\sqrt{x} - 2}{x -4}$
Direct substitution? $\frac{2-2}{4-4}$ Indeterminate, direct substitution fails!
Use algebra: multiply by the conjugate of $\sqrt{x}-2$:
\[\begin{align} &(\frac{\sqrt{x}-2}{x-4})(\frac{\sqrt{x}+2}{\sqrt{x}+2}) \\ = &\frac{x-4}{(x-4)(\sqrt{x}+2)} \\ = &\frac{1}{\sqrt{x}+2}. \end{align}\]So as $x \rightarrow 4$, $\frac{\sqrt{x}-2}{x-4} \rightarrow \frac{1}{4}$.
Exercise
Compute ${\displaystyle \lim_{x\rightarrow 9}\frac{\sqrt{x}-3}{x-9}}$.
Example
Compute ${\displaystyle \lim_{x\rightarrow 0}\frac{\sqrt{x+1}-1}{x}}$.
Direct substitution results in $\frac{0}{0}$. Indeterminate. So multiply by conjugate:
\[\begin{align} (\frac{\sqrt{x+1}-1}{x})(\frac{\sqrt{x+1}+1}{\sqrt{x+1}+1}) \\ = \frac{x+1-1}{x(\sqrt{x+1}+1)} \\ = \frac{x}{x(\sqrt{x+1}+1)} \\ = \frac{1}{\sqrt{x+1}+1}. \end{align}\]As $x \rightarrow 0$, this expression $\rightarrow \frac{1}{2}$
Wavy
Compute ${\displaystyle \lim_{x\rightarrow 0}} \sin(\frac{1}{x})$. What does this look like as $x \rightarrow 0$?
- Can pick small values of $x$: $\sin(\frac{1}{.00001})$?
- Smarter values of $x$ to use? I know what $\sin(\pi/2)$ is.
- What $x$ value is that, for $y = \sin(\frac{1}{x})$?
Use reciprocals of ones we know. So: $x = \frac{2}{\pi}$, $\frac{2}{99999\pi}$, etc.
Graph
What is going on?
Upcoming
- DeltaMath: Limits due tonight
- Textbook homework: due Monday, 9/15:
- Section 1.4 #216
- Section 2.2 #36, 38, 46, 48, 76
- Section 2.3 #84, 96, 128
- Write your answers neatly on paper, with your name and Calc I HW 3 written on the top. Staple all the pages together! Bring this in to class on Monday!
- We will go over some of these problems this Thursday! Be prepared to present some of your work / ask questions on problems you are confused on!
- DeltaMath: More Limits due Thursday, 9/19.
- Thursday: asynchronous lesson + small groups.
- We can work through some of the homework problems (come prepared with questions about them!), DeltaMath, etc.
- Can work through examples done in class or from the notes.