Calculus I Lesson 3: More on Limits

  1. Warm Up
    1. Graph
  2. Questions from DeltaMath?
  3. Recall
  4. Computing Limits
    1. Direct Substitution
    2. Algebraic Manipulation
    3. Exercise
  5. Conjugates
    1. Exercise
    2. Example
  6. Wavy
    1. Graph
  7. Upcoming

Warm Up

  1. Graph $f(x) = \frac{x^3-1}{x^2-1}$. (Graphing calculator / Desmos)
  2. For the points where $f(x)$ is not defined, does the graph of $f$ appear to approach a particular (finite) value?
  3. Use the distributive property to show $x^3 - 1 = (x-1)(x^2+x+1)$ and $x^2 - 1 = (x-1)(x+1)$.
  4. Simplify $\frac{(x-1)(x^2+x+1)}{(x-1)(x+1)}$.

Graph

Questions from DeltaMath?

Recall

Computing Limits

3 ways to compute limits:

  1. Direct substitution
  2. Algebraic manipulation
  3. Squeeze Theorem

Eventually: 4th way (l’Hôpital’s rule). If you know that: don’t use it yet.

Direct Substitution

Easiest method. Works for “nicely behaved functions”:

These functions are continuous.

Algebraic Manipulation

In other words: can we make our function equivalent to one of the ones where we can use direct substitution, except possibly at one, isolated point? (Ex: warm-up)

(Later: squeeze theorem.)

Exercise

Use algebraic manipulation to compute these limits:

Conjugates

${\displaystyle \lim_{x \rightarrow 4}}\frac{\sqrt{x} - 2}{x -4}$

Direct substitution? $\frac{2-2}{4-4}$ Indeterminate, direct substitution fails!

Use algebra: multiply by the conjugate of $\sqrt{x}-2$:

\[\begin{align} &(\frac{\sqrt{x}-2}{x-4})(\frac{\sqrt{x}+2}{\sqrt{x}+2}) \\ = &\frac{x-4}{(x-4)(\sqrt{x}+2)} \\ = &\frac{1}{\sqrt{x}+2}. \end{align}\]

So as $x \rightarrow 4$, $\frac{\sqrt{x}-2}{x-4} \rightarrow \frac{1}{4}$.

Exercise

Compute ${\displaystyle \lim_{x\rightarrow 9}\frac{\sqrt{x}-3}{x-9}}$.

Example

Compute ${\displaystyle \lim_{x\rightarrow 0}\frac{\sqrt{x+1}-1}{x}}$.

Direct substitution results in $\frac{0}{0}$. Indeterminate. So multiply by conjugate:

\[\begin{align} (\frac{\sqrt{x+1}-1}{x})(\frac{\sqrt{x+1}+1}{\sqrt{x+1}+1}) \\ = \frac{x+1-1}{x(\sqrt{x+1}+1)} \\ = \frac{x}{x(\sqrt{x+1}+1)} \\ = \frac{1}{\sqrt{x+1}+1}. \end{align}\]

As $x \rightarrow 0$, this expression $\rightarrow \frac{1}{2}$

Wavy

Compute ${\displaystyle \lim_{x\rightarrow 0}} \sin(\frac{1}{x})$. What does this look like as $x \rightarrow 0$?

Use reciprocals of ones we know. So: $x = \frac{2}{\pi}$, $\frac{2}{99999\pi}$, etc.

Graph

What is going on?

Upcoming